Home
Class 12
PHYSICS
If K(1) and K(2) are maximum kinetic ene...

If `K_(1) and K_(2)` are maximum kinetic energies of photoelectrons emitted when light of wavelength `lambda_(1) and lambda_(2)` respectively are incident on a metallic surface. If `lambda_(1)=3lambda_(2)` then

A

`K_(1)gt ((K_(2))/(3))`

B

`K_(1) lt ((K_(2))/(3))`

C

`K_(1)=3K_(2)`

D

`K_(2)=3K_(1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NTA JEE MOCK TEST 106

    NTA MOCK TESTS|Exercise PHYSICS|25 Videos
  • NTA JEE MOCK TEST 108

    NTA MOCK TESTS|Exercise PHYSICS|25 Videos

Similar Questions

Explore conceptually related problems

Let be the maximum kinetic energy of photoelectrons emitted by light of wavelength lambda_(1) and lambda_(2) correspondingto wavelength lambda_(2) . If lambda_(1) = 2lambda_(2) then:

The maximum kinetic energies of photoelectrons emitted from a metal are k_(1) and k_(2) when it is irradiated with light of wavelenght lambda_(1) and lambda_(2) respectively. Find work function of the metal.

Knowledge Check

  • If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(2) and lambda_(1) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then

    A
    `K_(1)gt((K_(2))/3)`
    B
    `K_(1)lt((K_(2))/3)`
    C
    `K_(1)=3K_(2)`
    D
    `K_(2)=3K_(1)`
  • If K_(1) and K_2 are the maximum kinetic energies of photo electrons emitted when lights of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface and lambda_(1) = 3lambda_(2) . Then

    A
    `K_(1) gt K_(2)//3`
    B
    `K_(1) lt K_(2)//3`
    C
    `K_(1) = 3K_(2)`
    D
    `K_(2) = 3K_(1)`
  • Let K_(1) be the maximum kinetic energy of photoelectrons emitted by a light of wavelength lambda_(1) and K_(2) corresponding to lambda_( 2). If lambda_(1) = 2lambda_(2) , then

    A
    `2K_(1) = K_(2)`
    B
    `K_(1) = 2K_(2)`
    C
    `K_(1) lt (K_(2))/(2)`
    D
    `K_(1) gt 2K_(2)`
  • Similar Questions

    Explore conceptually related problems

    The maximum kinetic energy of the photoelectrons emitted is doubled when the wavelength of light incident on the photosensitive surface changes from lambda_(1) to lambda_(2) . Deduce expressions for the threshold wavelength and work function for the metal surface in terms of lambda_(1) and lambda_(2) .

    Ki be the maximum kinetic energy of photoelectrons emitted when metal surface is illuminated by light of wavelength lambda_(1) . Similarly K_2 is corresponding to wavelength lambda_(2) for same metal. If lambda_(1) = 2lambda_(2) then

    A photomental is illuminated by lights of wavelenght lambda_(1) and lambda_(2) respectively. The maximum kinetic enegies of electrons emitted in the two cases are E_(1) and E_(2) respectively. The work function of metal is.

    A dye absorbs a photon of wavelength lambda and re - emits the same energy into two phorons of wavelengths lambda_(1) and lambda_(2) respectively. The wavelength lambda is related with lambda_(1) and lambda_(2) as :

    If lambda_(1) and lambda_(2) are the maximum wavelength limits of Lyman and Balmer series of H atom, (lambda_1)/(lambda_2) will be .