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A hollow charged metal sphere has radius...

A hollow charged metal sphere has radius `r`. If the potential difference between its surface and a point at a distance `3r` from the centre is V, then electric field intensity at a distance `3r` is

A

`(V)/(6r)`

B

`(V)/(4r)`

C

`(V)/(3r)`

D

`(V)/(2r)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10V . The potential at the distance 3 cm from the centre of the sphere is:

    A
    zero
    B
    `10 V`
    C
    same as at point 5 cm away from the surface
    D
    same as at a point `25 cm` away from the surface

  • A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10 V . The potential at a distance of 2 cm from the centre of the sphere

    A
    Zero
    B
    `10 V`
    C
    `4 V`
    D
    `10//3 V`

  • A sphere of radius R has a charge density sigma . The electric intensity at a point at a distance r from its centre is

    A
    `E=(sigmaR^(2))/(in_(0)kr^(2))`
    B
    `E=(sigma)/(in_(0)k)`
    C
    `E=R^(2)`
    D
    `E=in_(0)kr^(2)sigma^(2)`

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