" Evaluate "y=A sin(omega t-kx)dx

In the equation y = A sin (omega t - kx), obtain the dimensional formula of omega and k. Given x is distnace and t is time.

In the relation y = r sin ( omega t - kx) , the dimensions of omega//k are

In the relation y = r sin ( omega t - kx) , the dimensions of omega//k are

Phase difference between two waves y _(1) = A sin (omega t - kx) and y _(2)= A cos (omega t - kx) is ……

If there are equations of two waves y=Asin( omega t-kx) and z= A sin(omega t -kx) , then on superposition of the two waves, the amplitude of resultant wave is

In the equation y= a sin (omega t+ kx) t and x stand for time and distance respectively. What are the dimensions of omega//k ?

In the equation : y=a sin (omega t - kx), t and x stand for time and distnace respectively. Obtain the dimensional formula for omega and k.