A particle starts its motion from rest under the action of a constant force. If the distance covered in first `10 s` is `s_1` and the covered in the first `20 s` is `s_2`, then.

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S_1 and that covered in the first 20 seconds is S_2 then:

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S_1 and that covered in the first 20 seconds is S_2 then

A particle starts moving from the position of rest under a constant acceleration.It travels a distance x in the first 10 s and distance y is next 10 s,then:

A bus starts from rest and moves whith acceleration a = 2 m/s^2 . The ratio of the distance covered in 6^(th) second to that covered in 6 seconds is

A bus starts from rest and moves whith acceleration a = 2 m/s^2 . The ratio of the distance covered in 6^(th) second to that covered in 6 seconds is

A particle starting from rest with constant acceleration travels a distance x in first 2s and a distance y in next 2s then

A particle starts from rest with constant acceleration. It travels a distance x in the first 10 s and a distance y in the next 20 s. The relation between x and y is

A body starts from rest with a uniform acceleration of 2 m s^(-1) . Find the distance covered by the body in 2 s.