The conductivity of 0.1 n NaOH solution is 0.022 S`cm^(-1)`.When equal volume of 0.1 N HCl solution is added, the conductivity of resultant solution is decreased to 0.0055 S `cm^(-1)` . The equivalent conductivity of NaCl solution is :

The conductivity of "0.1N NaOH" solution is 0.022 S cm^(-1) . To this solution equal volume of " 0.1 N HCl solution is added which results into decrease of conductivity of solution to 0.0055 S cm^(-1) . The equivalent conductivity of NaCl solution in S cm^(2)" equiv"^(-1) is :

The conductivity of 0.35M solution of KCl at 300K is 0.0275 S cm^(-1) . Calculate molar conductivity

The conductivity of 0.35M solution of KCl at 300K is 0.0275 S cm^(-1) . Calculate molar conductivity

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S.cm^(-1) . Calculate the molar conductivity of the KCl solution.

The conductivity of 0.20M solution of KCl at 298 K is 0.0248S cm^(-1). Calculate molar conductance.

The conductivity of 0.35M NaCl solution at 298K is 0.025 S/cm. Calculate its molar conductivity .

The specific conductance (k) of a 0.1M NaOH solution is 0.0221 S cm^(-1) . On addition of an equal volume (V) of 0.10 M HCI solution, the value of specific conductance (k) falls to 0.0056 S cm^(-1) . On further addition of same volume (V) of 0.10 M HCI , the value of k rises to 0.017 S cm^(-1) . calculate equivalent conductivity (^^) for HCI in S cm^(2) mol^(-1) .