If the magnitude of two vectors are 4 and 6 and the magnitude of their scalar product is `12sqrt2` what is the angle between the vectors?

Explanation

`A = 4, B = 6 vec A. Vec B = 12 sqrt2`
`vec A. Vec B = AB cos theta`
`cos theta = (vec A. vecB )/(AB) = (12sqrt2)/(4 xx 6) = (1)/(sqrt 2)`
`cos theta = cos 45^(@)`
`therefore theta = 45^(@)`.