A particle is projected at ` 60(@)` to the horizontal with a kinetic energy `K` . The kinetic energy at the highest point is

Explanation

Initial kinetic energy is ` K = 1/2 mu^(2)`
The velocity at highest point `v_(x) = u cos theta`.
Kinetic energy of a particle at highest point
`K_(H) = 1/2 (mv_(x)^(2)) = 1/(2) mu^(2) cos^(2) theta`
` = K cos ^(2) 60^(@) = k/4`