A vehicle of mass `15` quintal climbs up a hill `200 m` high. It then moves on a level road with a speed of `30 ms^(-1)`. Calculate the potential energy gained by it and its total mechanical energy while running on the top of the hill.

Explanation

`m = 15 quintal = 1500 kg `,
`g = 9.8 ms^(-2), h = 200 m`
P.E gained, U = mgh = `1500 xx 9.8 xx 200 = 2.94 xx 10^(6) J`
`K.E = 1/2 mv^(2) = 1/2 xx 1500 xx (30)^(2)`
`= 0.675 x 10^(6)J`
Total mechanical energy `E = K + U =(0.675 + 2.94) xx 10^(6)`
`= 3.165 xx 10^(6)J`