A particle is released from height `H`. At cartain height from the ground its kinetic energy is twice its gravitational potential energy. Find the height and speed of particle at that height.

Explanation

`K.E = 2PE But KE = TE -PE `
`mg(H-h) = 2mgh, mgH = 3 mgh`
`Rightarrow h = (H)/3, Also K.E = 2P.E, `
`1/2 mv^(2) = 2mg(H/3) Rightarrow v = 2 sqrt(gH)/(3)`