The figure shown a particle sliding on a frictionless track, which teminates in a straight horizontal section. If the particle starts slipping from the point `A`, how far away from the track will the particle hit the ground?

Explanation

Applying the law of conservation of mechanical energy for the points A and B,
`mgH = 1/2 mv^(2) + mgh`
`g - (v^(2))/2 = g/2`
`or v^(2) = g Rightarrow v = sqrt g = 3.1 ms^(-1)`
After point B the particle exhibits projectile motion with `theta = 0^(@)` and ` y = -0.5m`
Horizontal distance travelled by the body
`R = u sqrt((2h)/(g) = 3.1 xx sqrt((2 xx0.5)/(9.8) = 1m`