The `50 N` collar starts from rest at `A` and is lifted with a constant speed of `0.6 m//s` along the smooth rod. Determine the power developed by the force `F` at the instant shown.
.

Explanation

Since the collar is lifted with a constant speed
`T cos theta - mg = 0 Rightarrow T cos theta = mg = 5 xx 10`
Now, P = vec F. Vec v = T cos theta xx v, Her T = F
`P = 50 xx v = 50 xx 0.6 = 30 W`