Home
Class 11
PHYSICS
With what angular velocity should a 20 m...

With what angular velocity should a 20 m long cord be rotated such that tension in it, while reaching the highest point, is zero

A

`0.5 rad/sec`

B

`0.2 rad/sec`

C

`7.5 rad/sec`

D

`0.7 rad/sec`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the angular velocity with which a 20 m long cord should be rotated such that the tension in it while reaching the highest point is zero, we can follow these steps: ### Step 1: Understanding the Forces at the Highest Point At the highest point of the vertical circular motion, the only forces acting on the mass at the end of the cord are its weight (mg) acting downward and the tension (T) in the cord. For the tension to be zero, the weight must provide the necessary centripetal force to keep the mass moving in a circular path. ### Step 2: Setting Up the Equation The centripetal force required for circular motion is given by: \[ F_c = \frac{mv^2}{r} \] At the highest point, the centripetal force is provided solely by the weight of the mass: \[ mg = \frac{mv^2}{r} \] Since the mass (m) appears on both sides of the equation, we can cancel it out: \[ g = \frac{v^2}{r} \] ### Step 3: Relating Linear Velocity to Angular Velocity We know that the linear velocity \( v \) can be expressed in terms of angular velocity \( \omega \) as: \[ v = \omega r \] Substituting this into our equation gives: \[ g = \frac{(\omega r)^2}{r} \] This simplifies to: \[ g = \omega^2 r \] ### Step 4: Solving for Angular Velocity Rearranging the equation to solve for \( \omega \), we have: \[ \omega^2 = \frac{g}{r} \] Taking the square root of both sides gives: \[ \omega = \sqrt{\frac{g}{r}} \] ### Step 5: Substituting Values Given that the length of the cord (which is the radius \( r \)) is 20 m and assuming \( g \approx 10 \, \text{m/s}^2 \): \[ \omega = \sqrt{\frac{10}{20}} \] \[ \omega = \sqrt{0.5} \] \[ \omega = \frac{1}{\sqrt{2}} \] ### Step 6: Calculating the Numerical Value Calculating \( \frac{1}{\sqrt{2}} \): \[ \omega \approx 0.707 \, \text{rad/s} \] ### Final Answer The angular velocity with which the cord should be rotated such that the tension in it while reaching the highest point is zero is approximately: \[ \omega \approx 0.707 \, \text{rad/s} \] ---
Promotional Banner

Topper's Solved these Questions

  • WORK , ENERGY & POWER

    NARAYNA|Exercise Evaluate Yourself - 5|9 Videos
  • WORK , ENERGY & POWER

    NARAYNA|Exercise Evaluate Yourself - 6|8 Videos
  • WORK , ENERGY & POWER

    NARAYNA|Exercise Evaluate Yourself - 3|7 Videos
  • WAVES

    NARAYNA|Exercise Exercise-IV|56 Videos
  • WORK POWER AND ENERGY

    NARAYNA|Exercise Level-VI (Integer)|12 Videos

Similar Questions

Explore conceptually related problems

What is the angular velocity of a particle lying on the axis of rotation ?

A hoop of radius r mass m rotating with an angular velocity omega_(0) is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it cases to slip ?

A hoop of radius r and mass m rotating with an angular velocity omega_0 is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases ot slip?

A projectile is thrown at angle of 30^(@) with a velocity of 10m/s .The change in velocity during the time interval in which it reaches the highest point is

A mass attached to a string rotates about a fixed centre with an angular velocity omega in a horizontal plane ,The length of the string and the angular velocity are now doubled .IF T_(0) is the initial tension in the string , then the new tension will be

A stone of mass 0.3 kg is tied to one end of a string 0.8 m long and rotated in a vertical circle. At what speed of the ball will the tension in the string be zero at the highest point of the circle? What would be the tension at the lowest point in this case ? Given g = 9.8 ms^(-2) ?

A stone of mass 0.3g is tied to one end of string 0.8m long and rotated in a vertical circle At what speed of the stone will the tension in the string be zero at the highest point of the circle ? What will be the tesion at the lowest point in this case ? Take g = 980 cm^(-2) .

A body is thrown vertically with an initial velocity of a m/sec. What altitude will it reach in t seconds ? Find the velocity of the body. In how many seconds and at what distance from the ground will the body reach the highest point ?

Assertion For looping a verticla loop of radius, r the minimum velocity at lowest point should be sqrt(5gr). Reason In this event the velocityh at the highest point will be zero.

The bob of a simple prendulum is suspended by a strinng of length 80 cm . What minimum horizontal velocity should be imparted to the bob so that it reaches it reaches the height of suspension point ? (g=10 m//s^(2))