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In the above problem the total KE before...

In the above problem the total `KE` before collision is

A

4500J

B

7500J

C

3000J

D

0J

Text Solution

Verified by Experts

The correct Answer is:
`(2)`
`KE_("before") = 1/2m_(1)u_(1)^(2) + 1/2 m_(2)u_(2)^(2)`
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