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The elastic potential enegry of a stretc...

The elastic potential enegry of a stretched spring is given by `E = 50 x^(2)`. Where `x` is the displacement in meter and and `E` is in joule, then the force constant of the spring is

A

50Nm

B

`100N m^(-1)`

C

`100N/m^(2)`

D

`100Nm`

Text Solution

Verified by Experts

The correct Answer is:
`(2)`
`U = 1/2 Kx^(2) (1), U = 50 x^(2) (2)`, compare equation(1) and (2) to find K
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NARAYNA-WORK , ENERGY & POWER -EXERCISE -1 (H.W)
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  2. A spring when compressed by 4 cm has 2 J energy stored in it. The forc...

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