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A particle moves with the velocity vec v...

A particle moves with the velocity `vec v = (5 vec i + 2 vec j - vec k) ms^(-1)` under the influence of a constant force, `vec F = (2 vec i + 5 vec j - 10 vec k)N`. The instantaneous power applied is

A

5 W

B

`10 W

C

20 W

D

30 W

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The correct Answer is:
To find the instantaneous power applied to the particle, we can use the formula for power in terms of force and velocity: ### Step 1: Understand the formula for instantaneous power The instantaneous power \( P \) can be calculated using the formula: \[ P = \vec{F} \cdot \vec{v} \] where \( \vec{F} \) is the force vector and \( \vec{v} \) is the velocity vector. ### Step 2: Write down the given vectors From the problem, we have: \[ \vec{v} = (5 \hat{i} + 2 \hat{j} - 1 \hat{k}) \, \text{m/s} \] \[ \vec{F} = (2 \hat{i} + 5 \hat{j} - 10 \hat{k}) \, \text{N} \] ### Step 3: Calculate the dot product Now, we will calculate the dot product \( \vec{F} \cdot \vec{v} \): \[ \vec{F} \cdot \vec{v} = (2 \hat{i} + 5 \hat{j} - 10 \hat{k}) \cdot (5 \hat{i} + 2 \hat{j} - 1 \hat{k}) \] Using the properties of dot product: \[ = (2 \cdot 5) + (5 \cdot 2) + (-10 \cdot -1) \] Calculating each term: \[ = 10 + 10 + 10 \] \[ = 30 \] ### Step 4: State the final answer Thus, the instantaneous power applied is: \[ P = 30 \, \text{W} \]

To find the instantaneous power applied to the particle, we can use the formula for power in terms of force and velocity: ### Step 1: Understand the formula for instantaneous power The instantaneous power \( P \) can be calculated using the formula: \[ P = \vec{F} \cdot \vec{v} \] where \( \vec{F} \) is the force vector and \( \vec{v} \) is the velocity vector. ...
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NARAYNA-WORK , ENERGY & POWER -EXERCISE -1 (H.W)
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