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A marble going at a speed of 2 ms^(-1) ...

A marble going at a speed of `2 ms^(-1)` hits another marble of equal mass at rest. If the collision is perfectly elastic, then the velocity of the first marble after collision is

A

`4 ms^(-1)`

B

`0 ms^(-1)`

C

`2 ms^(-1)`

D

`3 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
`(2)`

`vec v_(1) = ((m_(1)- m_(2))/(m_(1) + m_(2)))vec u_(1) + ((2m_(2))/(m_(1) + m_(2))) vec u_(2)`
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