A uniform rope of length `'L` and linear density `'mu'` is on a smooth horizontal table with a length `'l'` lying on the table. The work done in pulling the hanging part on to the table is

Options

A. `mug(L-l)^(2)/2`
B. `mug(L-l)^(2)/2l^(2)`
C. `mug(L-l)^(2)/2L^(2)`
D. `mug(L-l)^(2)/2(L-l)`

Answer

`(1)`

Explanation

`W = m^(1)gh = mu (L - l)g(L-l)/2`