In the figure shown all the surfaces are frictionless, and mass of the block 'm' is 1 kg. The block and wedge are held initially at rest. Now wedge is given a horizontal acceleration of `5 m/s^(2)` by applying a force on the wedge, so that the block does not slip on the wedge. Then work done by the normal force in ground frame on the block in 2 sec is :
` (##NAR_NEET_PHY_XI_P2_C06_E09_012_Q01.png" width="80%">

Options

A. 30 J
B. 50 J
C. 100 J
D. 150 J

Answer

`(2)`

Explanation

`Mg sin theta = ma cos theta, M = cot theta/2`
`N = Mg cos theta + ma sin theta = 5/sin theta`
` W = N x sin theta`
Where `x = 1/2 at^(2) = 10`