A car of mass `M` accelerates starting from rest. Velocity of the car is given by `v=((2Pt)/(M))^((1)/(2))` where `P` is the constant power supplied by the engine. The position of car as a function of time is given as

Options

A. `(8P/9M)^(1/2) t ^(3/2)`
B. `(9P/8M)^(1/2) t ^(3/2)`
C. `(8P/9M)^(1/2) t ^(2/3)`
D. `(9P/8M) t ^(3)`

Answer

`(1)`

Explanation

Here ` v = ((2Pt)/(M))^(1/2) or ds /dt = ((2Pt)/(M))^(1/2) or
ds = ((2Pt)/(M))^(1/2) dt. Integrate to find .s..`