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A stationary body explodes into two frag...

A stationary body explodes into two fragments of masses `m_(1)` and `m_(2)`. If momentum of one fragment is `p`, the energy of explosion is

A

`p^(2)/2(m_(1) + m_(2))`

B

`p^(2)/2 sqrt(m_(1)m_(2))`

C

`p^(2)(m_(1) + m_(2))/2m_(1)m_(2)`

D

`p^(2)/2(m_(1) - m_(2))`

Text Solution

Verified by Experts

The correct Answer is:
`(3)`
`E = E_(1) + E_(2) = (p_(1)^(2))/(2m_(1)) + (p_(2))/(2m_(2))`
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NARAYNA-WORK , ENERGY & POWER -EXERCISE -II (C.W)
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