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A bob is suspended from a crane by a cab...

A bob is suspended from a crane by a cable of length `l=5 m`. The crane and load are moving at a constant speed `v_(0)`. The crane is stopped by a bumper and the bob on the cable swings out an angle of `60^(@)`. The initial speed `v_(0)` is `(g=9.8 m//s^(2))`

A

`10 m/s`

B

`7 m/s`

C

`4 m/s`

D

`2 m/s`

Text Solution

Verified by Experts

The correct Answer is:
`(2)`
`1/2(mv_(0)^(2) = mgl(1 - cos 60^(@))`
`v_(0) = sqrt(2gl(1-1/2))`
`v_(0) = sqrt49`
`v_(0) = 7`
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