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A block of wood of mass 3M is suspended ...

A block of wood of mass `3M` is suspended by a string of length `(10)/(3) m`. A bullet of mass `M` hits it with a certain velocity and gets embedded in it. The block and the bullet swing to one side till the string makes `120^@` with the initial position. the velocity of the bullet is `(g=10 ms^(-2))`.

A

`40/sqrt3 ms^(-1)`

B

`20ms^(-1)`

C

`30ms^(-1)`

D

`40ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
`(4)`

`mu = (M + m) sqrt(2gl (1 -cos theta))`
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NARAYNA-WORK , ENERGY & POWER -EXERCISE -II (C.W)
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