Three particles A, B and C of equal mass move with equal speed V along the medians of an equilateral triangle as shown in hgure. They collide at the centroid G of the triangle. After the collision, A comes to test, B retraces its path with the speed V. What is the velocity of C ?

Options

A. v along BG
B. `v/2 along GB`
C. Zero
D. v along CG

Answer

`(1)`

Explanation

Along X -axis:
`0 + mv cos theta - mv cos theta = 0 - mv cos theta + mv_(x)`
`v_(x) = v cos theta (theta = 30^(@))`
Along Y - axis:
`- mv + mv sin theta + mv sin theta = 0 - mv sin theta + mv _(y)`
`v_(y) = v sin theta(theta = 30^(@)), ` `v_(net) = sqrt(v_(x)^(2) + v_(y)^(2))`