A chain AB of length `l` is located in a smooth horizontal tube so that its fraction of length `h` hangs freely and touches the surface of the table with its end B(figure). At a certain moment the end A of the chain is set free. With what velocity will this end of the chain slip out of the tube?

Options

A. `hsqrt(2g/Lh)`
B. `sqrt(2ghlog_(e)(L/h))`
C. `sqrt(2gl log_(e)(L/h))`
D. `1/hLsqrt2g`

Answer

`(2)`

Explanation

Let .x. be the length of chain inside the tube
`a = ((Mh)/L)g)/(M/L(h+x)` = `hg/h+x, -vdv/dx, -vdv/dx = hg/h+x`
on integrating both sides, -`int_(0)^(v) v dv = int_(l-h)^(0) hg/(h+x) dx`