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A particle is moving along a circle of f...

A particle is moving along a circle of fixed radius such thta the power 'P' delivered by all the forces acting on it varies with time t as shown in figure. The angular acceleration `alpha `of the particle varies as:

A

`t^(1/2)`

B

`t^(-1/2)`

C

`t`

D

`t^(3/2)`

Text Solution

Verified by Experts

The correct Answer is:
`(2)`

According to graph shown
`P = tau omega = constant`
`alpha = P /omega I`
`alpha = P /atI(because omega = alpha t)`
`a^(2) = P /It Rightarrow a = (sqrt(P/I))t ^(-1/2)`
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