A particle of mass `2 kg` starts moving in a straight line with an initial velocity of `2 m//s` at a constant acceleration of `2 m//s^(2)`. Then rate of change of kinetic energy.

Options

A. is four times the velocity at any moment
B. is two times the displacement at any moment.
C. is four times the rate of change of velocity at any moment.
D. is constant throughout

Answer

`(1)`

Explanation

`K = 1/2 (mv^(2))`
` therefore (dK)/(dt) = mv(dv)/(dt) = (m (dv)/(dt))v = (m a) v`