Two bodies move towards each other and collide inelastically. The velocity of the first body is `2 m//s` and that of the seconf is `4m//sec` before impact. The common velocity after collision is `1 m//s` in the direction of the first body. The number of times did the `KE` of the first body exceed that of the second body before collision.

Options

A. `4.25`
B. `3.25`
C. `2.25`
D. `1.25`

Answer

`(4)`

Explanation

Calculate` K.E_(1) and K.E_(2)` before collision
`therefore n = (K.E_(1))/(K.E_(2))`