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A body A moves towards a wall with veloc...

A body A moves towards a wall with velocity `V`. The wall also moves towards the body `A` with velocity `V_(0)`. After collision the body moves in opposite direction with velocity `V^(1)` which is `(1+(2V_(0))/(V))` times the velocity `V`. The coefficient of restitution is

A

`1/4`

B

`1/3`

C

`1`

D

`1/2`

Text Solution

Verified by Experts

The correct Answer is:
`(3)`

`e = (v_(2) - v_(1))/(u_(1) - u_(2)) = (- v_(0) + v^(1))/(v + v_(0))`
given `v^(1) = (1 + (2v_(0))/v)v`
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