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Let the nine different letters A, B, C...

Let the nine different letters ` A, B, C… I in {1, 2, 3, …, 9}`. Then find the probability that product `(A - 1)(B - 1) … (I - 9)` is an even number.

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To find the probability that the product \((A - 1)(B - 1) \ldots (I - 9)\) is an even number, we can follow these steps: ### Step 1: Identify the Values of \(A, B, C, \ldots, I\) The letters \(A, B, C, \ldots, I\) represent the numbers from the set \(\{1, 2, 3, \ldots, 9\}\). Therefore, each letter can take a unique value from this set. ### Step 2: Analyze the Expression \((A - 1)(B - 1) \ldots (I - 9)\) The expression consists of the terms \((A - 1), (B - 1), \ldots, (I - 9)\). We can rewrite these terms: - \(A - 1\) can take values from \(0\) to \(8\) (since \(A\) ranges from \(1\) to \(9\)). - \(B - 1\) can also take values from \(0\) to \(8\). - Continuing this for all letters, we see that each term will be one less than the corresponding number. ### Step 3: Determine the Parity of Each Term The values of \(A, B, C, \ldots, I\) can be either odd or even: - Odd numbers in the set \(\{1, 2, 3, \ldots, 9\}\): \(1, 3, 5, 7, 9\) (5 odd numbers) - Even numbers in the set: \(2, 4, 6, 8\) (4 even numbers) When we subtract \(1\) from these: - Odd numbers become even: \(0, 2, 4, 6, 8\) - Even numbers become odd: \(1, 3, 5, 7\) ### Step 4: Count the Even and Odd Factors From the analysis: - There are \(5\) terms that will be even (from odd numbers) and \(4\) terms that will be odd (from even numbers). ### Step 5: Determine the Conditions for the Product to be Even For the product \((A - 1)(B - 1) \ldots (I - 9)\) to be even, at least one of the factors must be even. Since we have \(5\) even factors available, it is guaranteed that at least one of the factors will be even. ### Step 6: Calculate the Probability Since it is certain that the product will always contain at least one even factor, the probability that the product is even is: \[ P(\text{Product is even}) = 1 \] ### Conclusion Thus, the required probability that the product \((A - 1)(B - 1) \ldots (I - 9)\) is an even number is: \[ \text{Probability} = 1 \] ---

To find the probability that the product \((A - 1)(B - 1) \ldots (I - 9)\) is an even number, we can follow these steps: ### Step 1: Identify the Values of \(A, B, C, \ldots, I\) The letters \(A, B, C, \ldots, I\) represent the numbers from the set \(\{1, 2, 3, \ldots, 9\}\). Therefore, each letter can take a unique value from this set. ### Step 2: Analyze the Expression \((A - 1)(B - 1) \ldots (I - 9)\) The expression consists of the terms \((A - 1), (B - 1), \ldots, (I - 9)\). We can rewrite these terms: - \(A - 1\) can take values from \(0\) to \(8\) (since \(A\) ranges from \(1\) to \(9\)). ...
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