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Words from the letters of the word PROBABILITY are formed by taking all letters at a time. The probability that both `B ' s` are not together and both `I ' s` are not together is `52//55` b. `53//55` c. `54//55` d. none of these

A

`52//55`

B

`53//55`

C

`54//55`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B

The total number of cases is `11!//(2! xx 2!)`. The number of favorable cases is `[11!//(2! xx 2!)] - 9!` Therefore, the required probability is
`=1 - (9! xx 4)/(11!) = (53)/(55)`
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