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Show that (i) p to (pvvq) is a tautolo...

Show that
(i) `p to (pvvq)` is a tautology
`(ii) (pvvq) ^^(~ p ^^~q)` is a contradiction

Text Solution

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(i) Truth values of `p to (pvvq)`

Thus, for all possible truth values of p and q, the compound statement `p to (pvvq) ` is true
Hence, ` pto (pvvq)` is a tautology
(ii) Truth values of `(pvvq) ^^(p^^~q)`

Thus, for all possible truth values of of p and q, then compound statements `(pvvq) ^^(~p ^^~q)` is false.
Hence, `(pvvq) ^^(~q ^^~q)` is a contradiction .
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