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Show that [(pvvq)vvr] harr [pvv(qvvr)] i...

Show that `[(pvvq)vvr] harr [pvv(qvvr)]` is a tautology

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Truth table of `[(pvvq)vvr] harr [pvv(qvvr)]`

Thus, for all possible truth values of p,q and r , the compound statements : `[pvvq)vvr] harr [pvv(qvvr)]` is true.
`:. [(pvvq)vvr] harr [pvv(qvvr)]` is a tautology.
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