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Prove that q^^~p -=~ (q to p)...

Prove that `q^^~p -=~ (q to p)`

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The correct Answer is:
`~(q to p ) -=~(~qvvp)`
`-=~ (~q)^^~p`
`-=q^^~p`
`~(q to p ) -=~(~qvvp)`
`-=~ (~q)^^~p`
`-=q^^~p`
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