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Prove that ~((~p)^^q) -=pvv(~q)....

Prove that `~((~p)^^q) -=pvv(~q)`.

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To prove that \( \neg((\neg p) \land q) \equiv p \lor (\neg q) \), we will use a truth table approach. Here’s a step-by-step solution: ### Step 1: Identify the Variables We have two variables, \( p \) and \( q \). We will consider all possible combinations of truth values for these variables. ### Step 2: Create a Truth Table We will create a truth table that includes the columns for \( p \), \( q \), \( \neg p \), \( \neg q \), \( \neg p \land q \), \( \neg((\neg p) \land q) \), and \( p \lor (\neg q) \). ...
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