Find the equation of the plane passing through the point `(2,3,1)` having `(5,3,2)` as the direction ratio is of the normal to the plane.

Explanation

The equation of the plane passing through `(x_(1), y_(1), z_(1))` and perpendicular to the line with direction ratios `a, b and c` is given by `a(x-x_(1))+b(y-y_(1))+c(z-z_(1))=0`.
Now, since the plane passes through (2, 3, 1) and is perpendicular to the line having direction ratios (5, 3, 2), the equation of the plane is given by `5(x-2)+3(y-3)+2(z-1)=0 or 5x+3y+2z= 21`.