If O be the origin and the coordinates of P be`(1," "2," "" "3)` , then find the equation of the plane passing through P and perpendicular to OP.

Explanation

Since `P(1, 2, -3)` is the foot of the perpendicular from the origin to the plane , OP is normal to the plane.
Thus, the direction ratios of normal to the plane are 1, 2 and -3.
Now, since the plane passes through ( 1, 2, -3), its equation is given by
`" "1(x-1)+2(y-2)-3(z+3)=0`
or `" "x+2y-3z-14=0`