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If the angle between the plane x-3y+2...

If the angle between the plane `x-3y+2z=1` and the line `(x-1)/2=(y-1)/1=(z-1)/(-3)i stheta,` then the find the value of `cos e cthetadot`

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Verified by Experts

The correct Answer is:
`2`
Vector normal to the plane is `vecn=hati-3hatj+2hatk` and vector along the line is `vecv= 2hati+hatj- 3hatk`
Now `" "sintheta = (vecx*vecv)/(|vecx||vecv|)= |(2-3-6)/(sqr(14)sqrt(14))|=|(7)/(14)|`
Hence, `cosec theta = 2`
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