the mirror image of point `(3,1,7)` with respect to the plane `x-y+z=3` is `P`. then equation plane which is passes through the point `P` and contains the line `x/1=y/2=z/1`.
A
`x+y-3z=0`
B
`3x+z=0`
C
`x-4y+7z=0`
D
`2x-y=0`
Text Solution
Verified by Experts
The correct Answer is:
C
Let image (x,y,z) of `therefore (x-3)/(1)=(y-1)/(-1)=(z-7)/(1)=-2((3-1+7-3)/(1^(2)+1^(2)+1^(2)))=-4` `P(x,y,z)=(-1,5,3)` plane passing through p(-1,5,3)is `a(x+1)+b(y-5)+c(z-3)=0` also plane contains line `(x)/(1)=(y)/(2)=(z)/(1)` `therefore (0,0,0)`satisfy `implies a-5b-3c=0` `and a+2b+c=0` from (2) and (3) pin in `(1)(X+1)-4(y-5)+7(z-3)=0` `or x-4y+7z=0`
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