The equation `[1x y][1 3 4 0 2-1 0 0 1]=[0]` has fo`ry=0` b. rational roots for `y=-1` d. integral roots Then (ii) a. (p) (r) b. (q) (p) c. (p) (q) d. (r) (p)

The roots of the given equation (p - q) x^2 + (q -r ) x + (r - p)=0 are

The roots of the equation (q-r)x^(2)+(r-p)x+(p-q)=0

If p,q,r epsilon R and the quadratic equation px^2+qx+r=0 has no real roots, then (A) p(p+q+r)gt0 (B) (p+q+r)gt0 (C) q(p+q+r)gt0 (D) p+q+rgt0

Let alpha,beta be the roots of the equation x^(2)-px+r=0 and alpha/2,2 beta be the roots of the equation x^(2)-qx+r=0. Then the value of r is (2)/(9)(p-q)(2q-p) b.(2)/(9)(q-p)(2q-p) c.(2)/(9)(q-2p)(2q-p) d.(2)/(9)(2p-q)(2q-p)

If p,q be non zero real numbes and f(x)!=0, in [0,2] and int_0^1 f(x).(x^2+px+q)dx=int_0^2 f(x).(x^2+px+q)dx=0 then equation x^2+px+q=0 has (A) two imginary roots (B) no root in (0,2) (C) one root in (0,1) and other in (1,2) (D) one root in (-oo,0) and other in (2,oo)