If `tan 2 alpha=(3)/(4)`, then find `tan alpha`.

If alpha=(pi)/(14), then the value of (tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha) is 1(b)1/2(c)2(d)1/3

If alpha=(2 pi)/(7), then tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha

" If alpha=(2 pi)/(7) ,then the value of tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha is "

If alpha = (2pi )/(7) , then tan alpha tan 2 alpha + tan 2 alpha tan 4 alpha + tan 4 alpha tan alpha =

If alpha=(2 pi)/(7) then tan alpha tan^(7)2 alpha+tan2 alpha tan4 alpha+tan2 alpha tan4 alpha=

tan(alpha+beta)=(1)/(2),tan(alpha-beta)=(1)/(3), then find the value of tan2 alpha

If 5tan alpha tan beta=3 , then find the value of (cos(alpha+beta))/(cos(alpha-beta))

If tan alpha.tan2alpha = 1 then find the value of cos2alpha .