`Ifint_0^oo(x^2dx)/((x^2+a^2)(x^2+b^2)(x^2+c^2))` `=pi/(2(a+b)(b+c)(c+a))` then the value of `int_0^oo(dx)/((x^2+4)(x^2+9))` (a) `pi/(60)` (b) `pi/(20)` (c) `pi/(40)` (d) `pi/(80)`

Given that int_0^oo(x^2)/((x^2+a^2)(x^2+b^2)(x^2+c^2))dx=pi/(2(a+b)(b+c)(c+a)) the value of int_0^oo(dx)/((x ^2+4)(x^2+9)), is pi/(60) b. pi/(40) c. pi/(20) d. pi/(80)

int_ (0)^(oo) (x^(2) dx)/((x^(2)+a^(2)) (x^(2)+b^(2)) (x^(2) +c^(2))) = (pi)/(2 (a+b) (b+c) (c+a)), then value of int_ (0)^(oo) (dx)/((x ^(2) +4) (x^(2) +9)) is (i) (pi)/(60) (ii) (pi)/(20) (iii) (pi)/(40) (iv ) (pi)/(80)

int_(0)^(oo)(x^(2))/((x^(2)+a^(2))(x^(2)+b^(2)))dx=(pi)/(2(a+b))

The value of the integral int_0^oox/((1+x)(1+x^2))dx is (pi^)/2 (b) (pi^)/4 (c) (pi^)/6 (d) pi/3

If int_(0) ^(infty ) x^(2)/((x^(2) + a^(2) ) (x^(2) + b^(2)) (x^(2) + c^(2)) )dx = pi/(2(a+b) (b + c) (c+ a)), then int_(0) ^(infty ) dx/((x^(2) + 25) (x^(2) + 36))=

The value of int_-1^3 [tan^-1(x/(x^2+1))+tan^-1((x^2+1)/x)]dx= (A) pi/2 (B) 2pi (C) pi (D) pi/4

The value of int_(0)^((pi)/(2))(dx)/(1+tan^(3)x) is (a) 0(b)1(c)(pi)/(2)(d)pi

int_(0)^((pi)/(2))(dx)/(a^(2)cos^(2)x+b^(2)sin^(2)x)=(pi)/(2ab)(a,b>0)

The value of int_(-pi/2)^(pi/2) (sin^2x)/(1+2^x)dx is: (A) pi (B) pi/2 (C) 4pi (D) pi/4

The value of int_(0)^( pi)(sin(1+(1)/(2))x)/(sin((x)/(2)))dx is,(a) n in I,n>=0(pi)/(2)(b)0(c)pi(d)2 pi