What volumes of ethyl alcohol and water must be mixed together to prepare 250 mL of 60 percent volume by volume solution of alcohol in water ?

Explanation

Volume percent = `("Volume of alcohol")/("Volume of solution")xx 100`
`60 = ("Volume of alcohol (x)")/(("250 mL"))xx 100`
or `x = (60 xx (250 mL))/(100) = 150 mL`
Volume of water = (250 - 150) = 100 mL