A gaseous mixture was prepared by taking equal moles of `CO` and `N_(2)`. If the total pressure of the mixture was found to be `1` atomosphere, the partical pressure of the nitrogen `(N_(2))` in the mixture is

Options

A. 0.8 atm
B. 0.9 atm
C. 1 atm
D. 0.5 atm

Answer

D

Explanation

Equal moles of CO and `N_(2)`
`n_(CO)=n_(N_(2))`
then, according to ideal gas equation, pressure of both gases CO and `N_(2)` becomes equal
`therefore" "P_(CO)=P_(N_(2))`
Given, `P_(CO)+P_(N_(2))`=Total pressure of mixture.
`"or "2P_(N_(2))=1"atm"`
`"or "P_(N_(2))=0.5"atm"`