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Solution of 0.1 N NH(4)OH and 0.1 N NH(4...

Solution of `0.1 N NH_(4)OH` and `0.1 N NH_(4)Cl` has `pH 9.25`, then find out `K_(b)` of `NH_(4)OH`.

A

`9.25`

B

`4.75`

C

`3.75`

D

`8.25`

Text Solution

Verified by Experts

The correct Answer is:
B
Solution of `NH_(4)OH` and `NH_(4)Cl` acts as a basic buffer solution. For basic buffer solution
`pOH=pK_(b)+log.(["salt"])/(["base"])`
`pOH=14-pH`
`=14-9.25=4.75`
`4.75=pK_(b)+log.(0.1)/(0.1)`
`pK_(b)=4.75`
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