Solubility of `MX_(2)` type electrolytes is `0.5xx10^(-4) mol//L`, then find out `K_(sp)` of electrolytes.

Options

A. `5xx10^(-12)`
B. `25xx10^(-10)`
C. `1xx10^(-13)`
D. `5xx10^(-13)`

Answer

D

Explanation

`underset("Solubility "0.5xx10^(-4)M)(M X_(2))rarrunderset(0.5xx10^(-4)M)(M^(2+))+underset(2xx0.5xx10^(-4)M)(2X^(-))` (on 100% ionisation)
`therefore K_(sp)` of `MX_(2)=[M^(2+)][X^(-)]^(2)`
`=(0.5xx10^(-4)) (1.0xx10^(-4))^(2)`
`=0.5x10^(-12)=5xx10^(-13)[M]^(3)`