`(1)/(4)(x-5)-(2)/(3)(x-2)=(1)/(3)`

3+(x)/(4)=(1)/(2)(4-(x)/(3))-(5)/(6)+(1)/(3)(11-(x)/(2))

The range of y=(sec^(2)x-|sec x|+4)/(sec^(2)x+|sec x|+4)is(1)[(3)/(5),1)(3)[(2)/(3),1)(4)[(1)/(3),1)

(5x)/(3)-(x-2)/(3)=(9)/(4)-(1)/(2)(x-(2x-1)/(3))

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)

Evaluate each of the following: ((2)/(11))^(4)x((11)/(3))^(2)x((3)/(2))^(3)((1)/(2))^(5)x((-2)/(3))^(4)x((3)/(5))^(-1)

((x-1)/(x-2))-((x-2)/(x-3))=((x-3)/(x-4))-((x-4)/(x-5))

The sum of the series (1)/(2)x^(2)+(2)/(3)x^(3)+(3)/(4)x^(4)+(4)/(5)x^(5)+... is :

(1)/(2(3x+4y))=(1)/(5(2x-3y))=(1)/(4),

The coefficient of x^(5) in the expansion of (1+(x)/(1!)+(x^(2))/(2!)+(x^(3))/(3!)+(x^(4))/(4!)+(x^(5))/(5!))^(2) is

Take away ((8)/(5)x^(2) - (2)/(3)x^(3) + (3)/(2)x -1) from ((x^(3))/(5) - (3)/(2)x^(2) + (2)/(3)x + (1)/(4))