The switch shown in figure is closed at `t=0` find the charge throuh battery till time `t=(L)/(R)`

Assertion : The switch S shown in the figure is closed at t = 0 . Initial current flowing through battery is (E)/(R + r) Reason : Initially capacitor was uncharged, so resistance offered by capacitor at t = 0 is zero

Assertion : The switch S shown in the figure is closed at t = 0 . Initial current flowing through battery is (E)/(R + r) Reason : Initially capacitor was uncharged, so resistance offered by capacitor at t = 0 is zero

The switch shown n the figure is closed at t=0 . The charge on the capacitor as a function of time is given by

The switch shown n the figure is closed at t=0 . The charge on the capacitor as a function of time is given by

In the circuit shown in figure switch S is closed at time t=0 Current I from the battery at time t is given by

In the circuit shown in figure switch S is closed at time t=0 Current I from the battery at time t is given by

The plates of a capacitor of capacitance C are given the charges Q_1 and Q_2 as shown in figure. Now the switch is closed at t =0. Find the charges on plates after time t.

In the circuit shown in figure switch S is closed at time t=0 . The charge which passes through the battery in one time constant is

In the circuit shown in figure switch S is closed at time t=0 . The charge which passes through the battery in one time constant is