According to Newton's law of gravitation , the force F between tow bodies of masses `m_1` and `m_2` placed at a distance of 'r' form each other is given as
`F = G xx (m_(1)xx m_(2))/r_(2)` , where G is the universal gravitional constant. Find the units of G in both C.G.S. and S.I. system.

The gravitational force F between two masses m_(1) and m_(2) separeted by a distance r is given by F = (Gm_(1)m_(2))/(r^(2)) Where G is the universal gravitational constant. What are the dimensions of G ?

Write an expression for the gravitational force of attraction between two bodies of masses m_1 and m_2 separated by a distance r .

Two bodies of masses m and 2m are kept at distance r apart from each other. Then the value of G varies as

According t Newton's law of gravitation,force between two point masses , m_1 and m_2 ,separated by a distance ,d is given by F=G (m_1 m_2)/(d^2) . Here,sonstant G depend on:

What is the dimensional formula of (a) volume (b) density and (c ) universal gravitational constant 'G' . The gravitational force of attraction between two objects of masses m and m separated by a distance d is given by F = (G m_(1) m_(2))/(d^(2)) Where G is the universal gravitational constant.

Gravitational force between two objects with mass m_(1)" and "m_(2) kept r distance apart is given as F_(G)= (Gm_(1)m_(2))/(r^2) , where G is gravitational constant. Express the relative error in F_(G) .

The gravitational force between two point masses m_(1) and m_(2) at separation r is given by F = k(m_(1) m_(2))/(r^(2)) The constant k doesn't