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Comprehension # 1 If net force on a sy...

Comprehension # 1
If net force on a system in a particular direction is zero (say in horizontal direction) we can apply:
`Sigmam_(R )x_(R )= Sigmam_(L)x_(L), Sigmam_(R )v_(R )= Sigmam_(L)v_(L)` and `Sigmam_(R )a_(R ) = Sigmam_(L)a_(L)`
Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is veloctiy and a the acceleration (all with respect to ground). A small block of mass `m = 1 kg` is placed over a wedge of mass `M = 4 kg` as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown.

Normal reaction between the two blocks at an instant when absolute acceleration of `m` is `5 sqrt3 m//s^(2)` at `60^(@)` with horizontal is ......... N. Normal reaction at this instant is making `30^(@)` with horizontal :-

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Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L), Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is veloctiy and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. Final velocity of the wedge is .......... m//s :-

Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L), Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is veloctiy and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. Final velocity of the wedge is .......... m//s :-

Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L), Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is veloctiy and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. The block will strike the x-axis at x = ............ m :-

Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L), Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is veloctiy and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. The block will strike the x-axis at x = ............ m :-

Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L), Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is veloctiy and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. At the same instant reaction on the wedge from the ground is ........N.

Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L), Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is veloctiy and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. At the same instant reaction on the wedge from the ground is ........N.

Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction), we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L) , Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. Final velocity of the wedge is .......... m//s :-

Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction) we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L), Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. At the same instant reaction on the wedge from the ground is ........N.

Comprehension # 1 If net force on a system in a particular direction is zero (say in horizontal direction), we can apply: Sigmam_(R )x_(R )= Sigmam_(L)x_(L) , Sigmam_(R )v_(R )= Sigmam_(L)v_(L) and Sigmam_(R )a_(R ) = Sigmam_(L)a_(L) Here R stands for the masses which are moving towards right and L for the masses towards left, x is displacement, v is velocity and a the acceleration (all with respect to ground). A small block of mass m = 1 kg is placed over a wedge of mass M = 4 kg as shown in figure. Mass m is released from rest. All surface are smooth. Origin O is as shown. The block will strike the x-axis at x = ............ m :-

If L and R denote inductance and resistance , respectively , then the dimensions of L//R are