The displacement `s` of a point moving in a straight line is given by:
`s = 8 t^(2) + 3t - 5`
`s` being in cm and `t` in s. The initial velocity of the particle is:

The displacement of a particle moving in a straight line, is given by s = 2t^2 + 2t + 4 where s is in metres and t in seconds. The acceleration of the particle is.

The displacement of a point moving along a straight line is given by s= 4t^(2) + 5t-6 Here s is in cm and t is in seconds calculate (i) Initial speed of particle (ii) Speed at t = 4s

The displacement of a point moving along a straight line is given by s= 4t^(2) + 5t-6 Here s is in cm and t is in seconds calculate (i) Initial speed of particle (ii) Speed at t = 4s

The displacement of a point moving along a straight line is given by s= 4t^(2) + 5t-6 Here s is in cm and t is in seconds calculate (i) Initial speed of particle (ii) Speed at t = 4s

The displacement of a particla moving in straight line is given by s=t^(4)+2t^(3)+3t^(2)+4 , where s is in meters and t is in seconds. Find the (a) velocity at t=1 s , (b) acceleration at t=2 s , (c ) average velocity during time interval t=0 to t=2 s and (d) average acceleration during time interval t=0 to t=1 s .

The displacement of a particle moving in a straight line is given by s=t^(3)-6t^(2)+3t+4 meters.The velocity when acceleration is zero is "

If S=t^(4)-5t^(2)+8t-3 , then initial velocity of the particle is

The distance s travelled by a particle moving on a straight line in time t sec is given by s=2t^(3)-9t^(2)+12t+6 then the initial velocity of the particle is

The displacement of a particle moving along a straight line is given by s=3t^(3)+2t^(2)-10t. find initial velocity and acceleration of particle.

The displacement of a particle moving in a straight line is described by the relation s=6+12t-2t^(2) . Here s is in metre and t in second. The distance covered by the particle in first 5s is